C6H5CHBr, C6H5CH(C6H5)Br,C6H5CH(CH3)Br,C6H5(C6H5)Br reactivity order
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Answer: The reactivity order of Sn1: 3°>2°>1° .
The reactivity order of Sn2: 1°>2°>3°
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Unfortunately, your question wrong because in the last option C₆H₅(C₆H₅)Br it does not exist like this because carbon has the valency of 4 and in the phenyl(benzene) all the carbon are connected there's no free space for the connectivty of Br in it.
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