Question

CA
35. Prove that the sum of three angles of a triangle is
180"​

Answer 1

Answer:

Step-by-step explanation:

FROM Δ ABC

draw a parallel line DE ║ BC

∠DAB + ∠BAC +∠CAE = 180

∠DAB = ∠ABC (ALTERNATE ANGLES ARE EQUAL)

∠CAE = ∠ACB (ALTERNATE ANGLES ARE EQUAL)

SO, ∠ABC + ∠ACB + ∠BAC =180

Answer 2

Answer:

see above picture. ....