CA=CD=BD,ANGLE DBC=35 AND ANGLE DCA=X FIND THE X VALUE
Answers
Answered by
4
Answer:
Step-by-step explanation:
Solution:-
Given : AC = BC, angle DCA = angle ECB and angle DBC = angle EAC
∠ DCA = ∠ ECB (Given)
Adding ∠ ECD to both sides, we get
∠ DCA + ∠ ECD = ∠ ECB + ∠ ECD
Addition property
∠ ECA = ∠ DCB.
AC = BC (Given)
∠ DBC = ∠ EAC (Given)
⇒ Δ DBC ≡ Δ EAC (By ASA postulate)
So, DC = EC (By CPCT)
Hence proved.
Attachments:
![](https://hi-static.z-dn.net/files/d93/60d986cb0edb133ea6a85b956327ce51.jpg)
Answered by
1
Answer:
VALUE OF X° = 40°
Step-by-step explanation:
Given,
CA = CD = BD
angle DBC = 35°
angle DCA = x°
To find,
value of x°
Solution:
angle CBD = angle BCD = 35°
angle BDC = [180 - ( 35 + 35 ) ] °
= ( 180 - 70 ) °
= 110°
angle CAD = ( 180 - 110 )° { linear pairs }
= 70°
angle CAD = angle CDA = 70°
angle DAC = [ 180 - ( 70 + 70 ) ] °
= (180 - 140 )°
= 40°
Attachments:
![](https://hi-static.z-dn.net/files/d9e/355939f7c628ee03b902236e5dab4780.jpg)
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