Question

Caclulate the concentration of OH- in aqueous solution having pH value 9.3.

Page 152 Chapter - 7.Acids, Bases and Salts

Answer 1

Answer:

The concentration of OH- in aqueous solution having pH value 9.3 is $1.99 \times 10^{-5}$

Explanation:

Given

pH = 9.3

Therefore,

pOH = 14 - 9.3 = 4.7   (∵ pH + pOH = 14)

We know that

pOH = -log[OH-]

or, [OH-] = 10^(-pOH)

              = $10^{-4.7}$

              = $10^{-4}\times 10^{-0.7}$

              = $1.99 \times 10^{-5}$

Therefore, he concentration of OH- in aqueous solution having pH value 9.3 is $1.99 \times 10^{-5}$

Hope this helps.