caesium and chloride ions are in contact along the body diagonal in a body centred cubic lattice .the edge lenght of the unit cell is 350pm and caesium has radius of 133pm. hence the radius of chloride ion is ?
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Answer:
Radius of Cl ion will be 175.79 pm.
Explanation:
In a body-centered cube lattice, for cesium chloride :
r = r ( cation ) + r ( anion )
r ( cation ) + r ( anion ) = √ 3 a/ 2
r (Cs+) + 181 = √3 x 141 / 2 = 356 . 79
r (Cl-) = 356.79 - 181 = 175.79 pm
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Explanation:
so the ans is 170pm....
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