Question

Calcium carbonate reacts with aqueous hcl to give cacl2 and co2 according to the reaction. calculate the mass of caco3 required to produce 11 grams of co2

Answer 1

The balanced chemical equation is

CaCO₃ + 2 HCl ---------> CaCl₂ + CO₂ + H₂O

According to the above equation, 1 mole of CaCO₃ gives 1 mole of CO₂.

So, if 1 mole of CO₂ is produced, then 1 mole of CaCO₃ is required.

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Now, number of moles of CO₂ = given mass/molar mass = 11/44 = 0.25

As, 0.25 moles of CO₂ is to be produced, 0.25 moles of CaCO₃ is needed.

Mass of 0.25 moles of CaCO₃ = 0.25 x 100 = 25 grams

∴ 25grams of CaCO₃ is required to produce 11grams of CO₂.

Hope it helps!!