Calculate ∧0 (CH2 ClOOH) if ∧0 values for HCl, KCl and CH2 ClCOOK are repectively, 4.261, 1.499 and 1.132 Ω-1 cm2 mol-1.
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Answered by
0
Answer:
Λ
0
(CH
3
COOH)=Λ
0
(CH
3
COOK)+Λ
0
(HCl)−Λ
0
(KCl)
=0.009+0.038−0.013=0.034 Sm
2
mol
−1
Also, Λ=
C
κ
=
0.001
2.72×10
−3
×10
−3
=2.72×10
−3
Sm
2
/mol.
The degree of the dissociation is given by the expression α=
Λ
0
Λ
=
0.034
2.72×10
−3
=0.08
Explanation:
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Answer:
sarl kijia
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