Question

calculate 33×33+33-33÷0​

Answer 1

$\huge{\red{\underline{\pink{\mathfrak{HeY, mAtE}}}}}$

33 × 33 + 33 - 33 ÷ 0​

➡️ 1,089 + 33 - 33 ÷ 0​

➡️ 1,122 - 33 ÷ 0

➡️ 1,089 ÷ 0

➡️ 0

Answer 2

To Find :- 33 × 33 + 33 - 33 ÷ 0 = ?

Concept used :- According to BODMAS rule,

• B - Bracket is solved first .
• O - of is solved at second .
• D - Then Division is solved .
• M - Then Multiplication is solved .
• A - The Addition is solved .
• S - Subtraction is solved in last .

Solution :-

→ 33 × 33 + 33 - 33 ÷ 0

using BODMAS rule, solving division first we get,

→ 33 × 33 + 33 - (33 ÷ 0)

→ 33 × 33 + 33 - undefined { Any number divisible by zero results to undefined }

using BODMAS rule, solving multiplication now we get,

→ (33 × 33) + 33 - undefined

→ 1089 + 33 - undefined

finally solving addition,

→ (1089 + 33) - undefined

→ (1122 - undefined) .

Conclusion :- There is no exact value for given problem .

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