Calculate acceleration due to gravity at a high of 300 km from the surface of the earth (m= 5.98×10^24kg, r=6400km
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Answer:
The acceleration due to gravity at a height of 300 km above the surface of the earth is 8.9 m/s^2
Explanation:
g = GM/R^2
Here
M = mass of the earth = 5.98 x 10^24 kg
R = radius of the Earth + the extra distance = 6400 + 300
= 6700 km = 6700000 m = 6.7 x 10^6 m
G = gravitational constant = 6.7 x 10^-11 N m^2/kg^2
=> g = 6.7 x 10^-11 x 5.98 x 10^24 / 6.7 x 6.7 x 10^12
=> g = 5.98 x 10^13 / 6.7 x 10^12
=> g = 0.89 x 10
=> g = 8.9 m/s^2 ( approx)
EXTRA:
Decrease %
decrease = 0.9
original = 9.8
Decrease % = 0.9/9.8 x 100
= 9.18 %
The acceleration due to gravity decrease by roughly 9.18% 300 km above the surface of the earth.
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