Question

calculate all quantum number of last three electron of oxygen.

Answer 1

Hey MATE!

Oxygen has the following electronic configuration :

1s2 2s2 2p4

The last three electrons exist in 2 nd shell so now :

1st electron :

n = 2
l = 1
m = -1
s = -1/2 (let us take this eleron to have negative spin and the other electron present in smae orbital has positive spin like the other 2 in other orbitals)

2nd electron :

n = 2
l = 1
m = 0
s = +1/2


3rd electron :

n = 2
l = 1
m = 1
s = +1/2

Hope it helps

Hakuna Matata :))