Question

Calculate empirical formula of compound whose %composion is - C-21.9%,H-4.6%,Br-73.4%.

Answer 1

Answer:

The relative numbers of atoms will be:

W%(C)/Ar ÷ W%(H)/ Ar ÷ W%(Br)/ Ar

21.9/12 ÷ 4.6/1 ÷ 73.4/80

1.83 ÷ 4.6 ÷ 0.92

Divide by lowest number (0.92):

1.99 ÷ 5 ÷ 1

Therefore simple ratio is:

2 ÷ 5 ÷ 1

The empirical formula of the compound is C2H5Br

Explanation:

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