Question

Calculate how many moles of NH3 form when 3.55 moles of N2H4 completely react according to the equation: 3N2H4 (l) ---> 4NH3 (g) + N2 (g) ?

Answer 1

here is your answer...!!!

I hope you understand my handwriting!!

Answer 2

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4.73

mol NH

3

Explanation:

What we're doing here is calculating basic mole-mole relationships, something that you'll be doing quite a bit!

The steps to solving mole-mole problems like this are

write the balanced chemical equation for the reaction (this is given)

divide the number of moles of the given known substance (3.55) by that substance's coefficient in the chemical equation (3)

multiply that number by the coefficient of the substance you're trying to find (4)

Using simple dimensional analysis, it looks like this:

3.55mol N2H4(←given amount)(4mol NH3(coefficient)3mol N2H4(coefficient))=4.73mol NH3

rounded to 3

significant figures, the amount given in the problem.

Thus, if the reaction goes to completion, 3.55 moles of N2H4 will yield 4.73 moles of NH3

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