Question

Calculate:

i). no. of moles in 3.011X1024 molecules of nitrogen.

ii). no. of molecules present in 9 g. of water.​

Answer 1

Explanation:

1) 6.023 x 10²³ molecules = 1 mole

so , 3.011 x 10²⁴ molecules = 3.011 x 10²⁴ x 1 / 6.023 x 10²³

= 5 moles

2) molar mass of water = 18 g

so, in 18g there are 6.023 x 10²³ molecules

so, in 9g it must be. 6.023 x 10²³ / 2 = 3.011 x 10²³ molecules