Chemistry, asked by sylaja39, 11 months ago

calculate kinetic energy of 5moles of nitrogen at 27degree centigrade

Answers

Answered by shirajulhoque74

0

Answer:

we have kinetic energy =3/2nRT

Temperature in kalvin=273k+27degree=300k

centigrade.

no.of mole given=5 moles of nitrogen.

therefore,n=5

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