Question

calculate molarity of 90% of H2 s o4 having density 1.98 gram per mole​

Answer 1

Answer:

Expert Answer:

Mass of solute in 100ml of solution = 90 g of H2SO4

Moles = Mass of solute in 100ml in solution = 90 = 0.9183. Molar mass 98.

Volume = mass X density.

Wt of 100ml of solution = 100 X 1.8 = 180 g.

Solution = solvent + solute.

180= x + 90.

x = 180 -90 = 90 g.

Molarity = No.

I sure you help

this answer

Answer 2

Explanation:

90gm of solute is present in 100g of SOLUTION

NO.mol of solute = 90/98 = 0.91

density of solution = 1.98g/ml

volume of solution = mass of solution/density of solution

= 100g/1.98g/ml

molarity of solution = no.of mol of solute/volume of solution

= [0.91/(100/1.98)]×1000

= 4.59M