Calculate no. of molecules in 1 drop of water having mass .05g
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Molecular mass of water = 18 g
No. of moles in 0.05 g of water = 0.05/18
= 2.78 x 10-3 mol
One mole = 6.023 x 1023 molecules
Therefore, 2.78 x 10-3 mol of water contain = 2.78 x 10-3 6.023 x 1023 molecules
= 1.67 x 1021 molecules
No. of moles in 0.05 g of water = 0.05/18
= 2.78 x 10-3 mol
One mole = 6.023 x 1023 molecules
Therefore, 2.78 x 10-3 mol of water contain = 2.78 x 10-3 6.023 x 1023 molecules
= 1.67 x 1021 molecules
cuckoo5:
Are you confirm that this was right answer
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okk
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Can I correct one mistake. It is the molar mass of water that is 18 grams and not the molecular mass which is 18 unified mass (u)
matlab
Answered by
1
First find no. of moles in 1 drop
So Molar mass = 18
n = m / M
= 0.05 / 18
= 0.002 moles
Now
1 mole contains 6.022 × 10^23 molecules
0.002 contains 0.002 × 6.022 × 10^23
1.20 × 10^21 molecules
Thanks
So Molar mass = 18
n = m / M
= 0.05 / 18
= 0.002 moles
Now
1 mole contains 6.022 × 10^23 molecules
0.002 contains 0.002 × 6.022 × 10^23
1.20 × 10^21 molecules
Thanks
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