Math, asked by bhumi9024, 1 year ago

calculate the amount and compound interest on 15000 for 2 years at 10% per annum compounded annually

Answers

Answered by isafsafiya
96

Answer:

c.i = 3150

Step-by-step explanation:

solution-------->

Given

  • P = 15000
  • N = 2
  • R = 10%

now as we know formula

a = p  (  {1 +   \frac{r}{100}})^{n}  \\  \\ put \: all \: the \: value \\  \\ a = 15000( {1 +  \frac{10}{100} })^{2}  \\  \\  \:  \:  \:  \:  = 15000 \times    { (\frac{110}{100} })^{2}  \\  \\  \:  \:  \:  \:  = 15000 \times  \frac{110}{100}  \times  \frac{110}{100}  \\  \\  \:  \:  \:  \:  = 150 \times 11 \times 11 \\  \\  \:  \:  \:  = 150 \times 121 \\  \\ a \:  \:  = 18150 \\  \\ no w \: for \: compound \: intrest \:  \\  \\ c.i = a \:  - p \\  \\ c.i = 18150 - 15000 \\  \\ c.i = 3150

Answered by gadakhsanket
20

Dear Student,

● Answer -

Compound interest = 3150 Rs

● Explaination -

# Given -

P = 15000 Rs

r = 10 % per annum

t = 2 years

# Solution -

Compound interest over sum p is given by formula -

CI = P [(1+r)^t - 1]

CI = 15000 [(1 + 10/100)^2 - 1]

CI = 15000 [(1+0.1)^2 - 1]

CI = 15000 [1.1^2 - 1]

CI = 15000 [1.21 - 1]

CI = 15000 × 0.21

CI = 3150 Rs

Therefore, compound interest is 3150 Rs.

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