Question

calculate the amount and the compound interest by using the formula for compound interest principal 1000, rate 10% , time 2 year​

Answer 1

Step-by-step explanation:

Here, Principal P = Rs. 1000 

R =10% per annum and n=2 years

∴ Amount after 2 years = P (1+200R)2n

= Rs. 1000×(1+20010)2×2=Rs.1000×(1+201)4=Rs.1000×(2021)4

= Rs.1000×2021×2021×2021×2021=Rs.1215.50 

Hence, compound interest = Amount - Principal

=Rs.1215.50−Rs.1000=Rs.215.50

Answer 2

Answer:

Amount =Rs.1210

Compound Interest=Rs.210

Step-by-step explanation:

Given:

Principal p= Rs.1000

n=2 years

r=10%

$A=p(1+\frac{r}{100} )^{n}$

$A=1000(1+\frac{10}{100} )^{2}$

$A=1000(\frac{100+10}{100} )^{2}$

$A=1000(\frac{110}{100} )^{2}$

$A=1000(\frac{110}{100} )(\frac{110}{100} )$

$A=10(\frac{11}{1} )(\frac{11}{1} )$

$A=10(11} )({11} )$

$A=10(121)$

$A=Rs.1210$

Amount =Rs.1210

To find compound interest

C.I=Amount-principal

Amount=Rs.1210

Principal=Rs.1000

C.I=1210-100

C.I=Rs.210