calculate the area other than the area common between two quadrants of circles of radius 16 cm each which is shown as the shaded region
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64
Answer is-
Since these are 2 quadrants so area shared is in the form of 2 segments.
Area of the shaded region is area of 2 shaded minor segments.
Area of shaded region 1= area of sector - area of triangle
= (90/360*22/7*8*8) - (1/2*8*8)
= (50.28 - 32)sqcm
= 18.28 sq cm
So, area of shaded region 2 = area of sector - area of triangle
= (90/360*22/7*8*8) - (1/2*8*8)= (50.28 - 32)sqcm
= 18.28 sq cm Area of shaded region
= 18.28 sq cm+18.28 sqcm
= 36.56 sq cm
Since these are 2 quadrants so area shared is in the form of 2 segments.
Area of the shaded region is area of 2 shaded minor segments.
Area of shaded region 1= area of sector - area of triangle
= (90/360*22/7*8*8) - (1/2*8*8)
= (50.28 - 32)sqcm
= 18.28 sq cm
So, area of shaded region 2 = area of sector - area of triangle
= (90/360*22/7*8*8) - (1/2*8*8)= (50.28 - 32)sqcm
= 18.28 sq cm Area of shaded region
= 18.28 sq cm+18.28 sqcm
= 36.56 sq cm
Answered by
10
Answer:
hope it helps u my answer is little bit less than that given in book
but I think my is correct
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