Chemistry, asked by amitrathor2261, 11 months ago

Calculate the atomic number of hydrogen like species which can be ionized by an electron moving with a velocity, v = 6.56 106 m s-1

Answers

Answered by ArunSivaPrakash
12

The atomic number is Z = 3

  • Given, Velocity of the electron = 6.56 * 10^6 m/s.
  • We know, for Hydrogen like species,    Velocity of an electron is calculated by formula :
  • V = (Z/n) * 2.18 * 10^6    , where 2.18*10^ 6 is velocity of an electron in 1st orbit of hydrogen, Z is atomic number, n is orbital number.
  • Now, by substituting the given data,   6.56 * 10^6 = (Z/n) 2.18 * 10^6
  • Let Z = 1 first calculate the n for Hydrogen atom
  • n = 2.18 / 6.56  = 0.332 ≈ 1  ( n is always a whole number)
  • Now, for hydrogen like atom having velocity of electron = 6.56 * 10^6 m/s in orbital 1
  • 6.56 * 10^6 = 2.18 * 10^6 ( Z /1)
  • Z = 3.009  ≈ 3
  • Therefore, the atomic number of hydrogen like species which can be ionized by an electron moving with a velocity, v = 6.56 106 m s-1 is 3
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