Question

Calculate the average current in a wire if a charge of 3500 C passes in 9 seconds

Answer 1

$\huge\underline{\underline{\bf \orange{Question-}}}$

Calculate the average current in a wire if a charge of 3500 C passes in 9 seconds

$\huge\underline{\underline{\bf \orange{Solution-}}}$

$\large\underline{\underline{\sf Given:}}$

• Charge (Q) = 3500 C
• Time (t ) = 9 sec

$\large\underline{\underline{\sf To\:Find:}}$

• Average Current (i)

We know ,

❏$\large{\boxed{\bf \blue{i=\dfrac{Q}{t}} }}$

$\implies{\sf i = \dfrac{3500}{9} }$

$\implies{\bf \red{ i = 388.8 A} }$

Answer 2

$\huge \fcolorbox{red}{pink}{Solution :)}$

Given ,

Change (q) = 3500 C

Time (t) = 9 sec

We know that , the rate of unit charge is called current , so

$\mathtt{ \large \fbox{Current = \frac{q \: }{ \: t \: } }}$

Substitute the known values , we get

Current = 3500/9

Current = 388.8 ampera

Hence , the current is 388.8 ampera

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