Calculate the charge density when a potential function x2 + y2 + z2 is in air(in 10-9 order)
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Given : Potential function, V(x,y, z) = x² + y² + z² is in air (in 10^9 order)
To Calculate : The charge density ( ρ )
solution : we know according to Poisson's equation, |∆²V| = ρ/ε
|∆²V| = δ²V/δx² + δ²V/δy² + δ²V/δz²
= δ²(x² + y² + z²) /δx² + δ²(x² + y² + z²)/δy² + δ²(x² + y² + z²)/δz²
= 2 + 2 + 2 = 6
so, 6 × 10^9 = ρ/ε .........(1)
we know , 1/4πε = k = 9 × 10^9
so, 1/ε = (9 × 10^9 × 4π) putting in equation (1) we get,
6 × 10^9 = ρ × 9 × 10^9 × 4π
⇒ρ = 6/36π = 1/6π units
Therefore the charge density will be 1/6π units.
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