Question

calculate the concentration of nitric Acid in mol/L in a sample which has a density 1.41 g/ml and the mass percent of nitric acid in it being 69%​

Answer 1

Answer:

u just need to apply the given formula in sol..here ur sol with calculations

answer can be 15.4 approx

Answer 2

Answer:

15.45 mol/L

Explanation:

we know that

molality = M = no. of moles / volume = mol/ L

here,

no. of moles = [ density(d) X mass percent( m% )X 10 ]

d = 1.41 g/mL

m% = 69 %

and molar mass of HNO3 = 1 + 14 + 48 = 63.

M = (69 X 1.41 X 10 ) / 63

M = 15.45 mol / L

HOPE it HELPS U