Question

calculate the de Broglie wavelength associated with Alpha particle of energy 7.7 into 10 raise to minus 13 and mass of 6.6 into 10 raise to minus 24 gram​

Answer 1

Explanation:

lambda = h/p

= h/mv

lampda/h = 1/mv

mv/c = hc/lambda

mv /c = E

from here find ' v'

then substitute that it the equation

Lambda = h/mv

from here find lambda

Answer 2

Explanation:

firstly, find out velocity from KE formula, put the value of v in the formula of wavelength .