calculate the decrease in the kinetic energy of a moving body if its velocity reduces to half of the initial velocity......??
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Answer:
K.E=0.5×m×v ^2
K.E(new)=0.5×m×(v/3) ^2
K.E(new)=0.5×m×v ^2 /9
K.E−K.E(new)=(1−1/9)0.5×m×v ^2 =(8/9)0.5×m×v ^2
Explanation:
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