calculate the dynamic viscosity of an oil used for lubrication a square plate 0.8m by 0.8m and an inclined plan with angle of inclination of 30. the weight of the plate is 30N and uniform velocity of 0.3ms. the thickness of the oil firm 1.5mm.
Answers
Answer:
I don't know sorry brother 0.9 and lol
Answer:
dynamic viscosity= 11.71 poise or 1.17N-s/m2
Explanation:
since plate is inclined upper portion of plate is square shaped and area is 0.8×0.8m
weight of plate is 300N acting downwards i.e acting perpendicular to the plane.
velocity of plate is 0.3m/s acting towards the sliding direction of plate i.e parallel to the plane.
these two are resolved into components
components of weight W, along the plane (parallel to plane)
=W×sin(30)
=300×sin(30)
=150N
shear stress=force/area
=150/0.8×0.8
shear stress=234.375N/m2
shear stress=dynamic viscosity×(dv/dy)
dynamic viscosity=shear stress×dy/dv
=234.375*1.5×10*(-3)/0.3
=1.17N-s/m(2) or
=11.71 poise