Question

calculate the empirical formula of a compound containing 87.5% by mass of nitrogen and 12.5% by mass of hydrogen( atomic weight of nitrogen is 14 and hydrogen is 1.)​

Answer 1

Answer:

N6H

Explanation:

n=87.5/14=6.25

h=12.5/12=1.0416

simplest form

N   6.25/1.0416=6.00

H     1.0416/1.0416=1

N6H