Question

Calculate the energy dissipated in kWh and J for a bulb of 250W, which is used for 6 hours.

Answer 1

E = 250*6*3600j =25*6*36 kwh

Answer 2

Energy dissipated, E = 1.5 kWh and E = 5400000 Joules

Explanation:

Given that,

Power of the bulb, P = 250 W

Time, t = 6 hours = 21600 s

The electric power is defined as the energy dissipated per unit time. It is given by :

$P=\dfrac{E}{t}$

$E=P\times t$

$E=250\ W\times 6\ h$

E = 1500 Wh

or

E = 1.5 kWh

Energy,

$E=P\times t$

$E=250\ W\times 21600\ s$

E = 5400000 Joules

or

$E=5.4\times 10^6\ J$

Therefore, this is the required solution.

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Calculate the energy dissipated in kWh and J for a bulb of 250 W, which is used for 6 hours.

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