sin theta -cos theta plus one / sin theta plus cos theta minus one is equal to one divided by sec theta minus tan theta
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Answer:
Step-by-step explanation:
sinФ - cosФ + 1/ sinФ + cosФ - 1
=Multiplying Numerator and Denominator by ( 1 - sinФ), we get
( 1 - sinФ)*(sinФ - cosФ + 1)/(sinФ + cosФ - 1)*( 1 - sinФ),
Simplifying Numerator we get,
(sinФ - cosФ + 1 -sin²Ф + sinФcosФ - sinФ )/(sinФ + cosФ - 1)*( 1 - sinФ)
=(-cosФ + cos²Ф + sinФcosФ )/(sinФ + cosФ - 1)*( 1 - sinФ),
Now, taking cosФ in common out of Numerator, we get
=cosФ *(-1 + cosФ + sinФ )/(sinФ + cosФ - 1)*( 1 - sinФ)
= cosФ / 1 - sinФ,
Now, Dividing Numerator and Denominator by cosФ , we get
= 1/secФ-tanФ.
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