Question

Calculate the energy required to pump an election from ground to the 2nd excited state in a metal of length 10 power minse 10

Answer 1

wavelength = 10^-10

now according to question



10^-10 = 13.6/ hc {1/n² -1/ n )


second excited State means = 3 orbit

so ,

h = Planck constant = 6.66× 10^-34


c = 3.08 × 10^8 m / s



10^ -10 = 13.6 / hc { 1/9



So energy comes out to be =>

10^-10 × 9 / 13.6 = hc


kindly do calculation for answer !!

hope it help you !!


thanks