Question

Calculate the following:-

a) The mass of 1.0505x10 [to the power 23 ] molecules of CO2[carbon dioxide]

Answer 1

Chemical Reactions,

We have,

1.0505x10²³molecules of CO2.

Have to find the mass.

Now 1 mole(6.023×10²³no.of molecules) of CO2 weights (12 + 2×16) = 44gm

So 1 molecule will weight = (44/6.023×10²³)gm

Therefore 1.0505x10²³molecules will weight = (44/6.023×10²³)×1.0505x10²³ gm [by cancelling out 10²³]

= 44/6.023×1.0505 gm

= 44000/6023 × 10505/10000 gm

= 7.675 gm [approximately]

So the mass of 1.0505 × 10²³molecules of CO2 is = 7.675 [approximately]

That's it
Hope it helped (^_^)/