calculate the force between two charge each of 20 micro Coulomb's in a medium of relative permittivity 4.. the distance between the two charges in 40cm.
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slattttttttt
Explanation:
vishalbabu9:
answer
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Answer:
Explanation:f'=f/k.
9×10^9×400×10^-12÷
4×1600×10^-4
=90÷16
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