Calculate the force required to take away a flat circular plate of radius 0.01 m from the surface of water. The surface tension of water is 0.075N / m. (Ans : 0.004713 N)
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Answered by
7
Hey mate ^_^
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Answer:
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T (Surface tension of water) = 0.075 N/m
F = 2 π R × T
=> As the interface between the water, plate and air is a circle of radius R.
F = 2 × π × 0.01 × 0.075 N
= 0.00471 N
#Be Brainly❤️
=======
Answer:
=======
T (Surface tension of water) = 0.075 N/m
F = 2 π R × T
=> As the interface between the water, plate and air is a circle of radius R.
F = 2 × π × 0.01 × 0.075 N
= 0.00471 N
#Be Brainly❤️
Answered by
6
➡️Surface tension of water = T = 0.075 N/m
➡️For a circular plate the force required is F = 2 π R * T
➡️as the interface between the water, plate and air is a circle of radius R.
F = 2 * π * 0.01 * 0.075 Newtons
= 0.00471 Newtons
= 471 dynes
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