Question

Calculate the heat required to make 6.4 Kg CaC2 from CaO(s) and C(s) from the reaction: CaO(s) + 3 C(s) → CaC2(s) + CO (g) given that ∆f Ho (CaC2) = -14.2 kcal. ∆f H° (CO) = -26.4 kcal.


​

Answer 1

Answer:

$co2 \: means \: wr349 \frac{789y1 \times \frac{?}{?} }{?} 238 {9131}^{?16} = 97845 \\ {8}^{2} 857 \frac{31}{79?}$