calculate the length of the DNA of bacteriophage lambda that has 48502 base pairs?
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Distance between two pairs=0.34nm=0.34×10^-9m/bp
Total number of base pairs given are 48502
Therefore Total length of DNA=0.34×10^-9m/bp×48502=16490.68×10^-9 =16.49×10^-6m
Thank you
Total number of base pairs given are 48502
Therefore Total length of DNA=0.34×10^-9m/bp×48502=16490.68×10^-9 =16.49×10^-6m
Thank you
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