Question

calculate the mass of 0.5 mole of
silver ii) 0.5 mole of sugar(Cl2H22O11)(at masses Ag=
108,c=12,h=1,o=16)​

Answer 1

Answer:

54g and 171g

Explanation:

n= w/M

i) 0.5 = w/ 108

w= 0.5×108

= 54g

ii) M= 12×12+1×22+16×11

= 342 u

0.5= w/ 342

w= 0.5×342

= 171g