Question

calculate the mass of carbon tetrachloride can be produced by the reaction of 144 gram of carbon with 71 gram of chlorine​

Answer 1

Answer:

C + 2 Cl2 → CCl4

Mass of Carbon = 144 g

Number of moles of Carbon =

$= \frac{ mass \: }{moleculr \: mass}$

$= \frac{144}{12}$

= 12

$= Mass \: of \: Chlorine \: = \: 71 \: g \: </p><p>Number of moles of chlorine =$

$</p><p>Number \: of \: moles \: of \: chlorine \: = \: \\ = \frac{71}{71} \\ \\ = 1mole$

Hence, chlorine is the limiting reagent.

According to the reaction, 2 moles of chlorine give 1 mole of CCl4.

So, 1 mole of chlorine will give 0.5 mole of CCl4.

Hence, mass of CCl4 =

moles×molecular mass of CCl4 = 0.5×154.0 =77gm ..

$thanks..........$