calculate the mass percent of different element present in sodium sulphate Na2so4
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7
Na mass%=46/142×100
=2300/71%
S %= 32/142×100
=1600/71%
O%=64/142×100
= 3200/71%
=2300/71%
S %= 32/142×100
=1600/71%
O%=64/142×100
= 3200/71%
Answered by
0
Answer:
Molar mass of Na2SO4 = [(2 × 23.0) + (32.00) + 4 (16.00)] = 142 g
Mass percent of an element = (Mass of that element in compound/Molar mass of that compound) × 100
∴ Mass percent of sodium (Na): (46/142) × 100 = 32.39%
Mass percent of sulphur(S): (32/142) × 100 = 22.54%
Mass percent of oxygen:(O): (64/142) × 100 = 45.07%
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