calculate the mass percentage of each element in water
Answers
Answered by
48
molecular mass of water (H2O) = 2×(mass of 1 H atom) + mass of O atom
=> molecular mass = 2×1+16
=> molecular mass = 2+16 = 18u
mass percentage of hydrogen = mass of hydrogen in water / molecular mass of water × 100
=> mass % of hydrogen = 2/18×100
=> mass % of hydrogen = 100/9 = 11.1%
mass % of oxygen = (100-11.1)%= 88.9%
hope this helps
=> molecular mass = 2×1+16
=> molecular mass = 2+16 = 18u
mass percentage of hydrogen = mass of hydrogen in water / molecular mass of water × 100
=> mass % of hydrogen = 2/18×100
=> mass % of hydrogen = 100/9 = 11.1%
mass % of oxygen = (100-11.1)%= 88.9%
hope this helps
Answered by
10
Answer:
Mark as Brainliast
Explanation:
Molecular mass of H2O=2*1+16=18u
Percentage of H in H2O= 2/18*100=11.11%
Percentage of O in H2O= 16/18*100=88.99%
Similar questions