Question

Calculate the maximum horizontal distance travelled by a ball theown with velocity 40m/s without hitting the ceiling of auditorium of height 25m

Answer 1

Answer:

20√55m

Explanation:

given u=40m/s

maximum height=25m

therfore

H = u²sin²∅/2g

25= (40)² × sin²∅/2× 10

25 = 80 × sin²∅

Sin²∅ = 25/80

Sin∅ = 5/4√5

Cos∅ = √55/4√5

Now, horizontal range = u²sin2∅/g

= (40)²× 2sin∅×cos∅/g

= 160 × 2 × 5/4√5 × √55/4√5

= 20√55 m