Question

if. x/xa+yb+zc=y/ya+zb+xc=z/za+xb+yc
and x+y+z notequal to 0 then each ratio is???​

Answer 1

Answer:

GIven,

x/(xa+yb+zc) = y/(ya+zb+xc) = z/(za+xb+yc)

we know from property of ratio,

a/b = c/d = e/f = (a+c+e)/(b+d+f)

so,

• x/(xa+yb+zc) = y/(ya+zb+xc) = z/(za+xb+yc) = (x+y+z)/(xa+yb+zc+ya+zb+xc+za+xb+yc)

• x/(xa+yb+zc) = y/(ya+zb+xc) = z/(za+xb+yc) = (x+y+z)/(xa+xb+xc+ya+yb+yc+za+zb+zc)

• x/(xa+yb+zc) = y/(ya+zb+xc) = z/(za+xb+yc) = (x+y+z)/{x(a+b+c)+y(a+b+c)+z(a+b+c)}

• x/(xa+yb+zc) = y/(ya+zb+xc) = z/(za+xb+yc) = (x+y+z)/{(a+b+c)(x+y+z)}

• x/(xa+yb+zc) = y/(ya+zb+xc) = z/(za+xb+yc) = 1/(a+b+c)    (Ans.)

Step-by-step explanation: