Chemistry, asked by CharanMultani7920, 11 months ago

Calculate the molality of 1 litre solution of 93% h2 s o4 weight by volume the density of solution is 1.84 gram per ml

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Answered by vipindesale2001

Answer:

Explanation:

Given, 93% H2SO4 solution (weight/volume). It means 93 g of H2SO4 present in 100 mL of solution, therefore, weight of H2SO4 = 93 g Volume of solution = 100 mL .'. Weight of solution = 100 x 1.84 = 184 g

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