calculate the molality of a solution containing 10 gram of NaOH in 200 cm cube of solution. Density of solution is 1.4 grams per Mole
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10ngramnaho2200cm cube
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Given:
Volume of solution = 200 cm³
Weight of NaOH = 10 gm
Density of solution = 1.4 gm/mol
To find:
The molality of the solution.
Solution:
We know that Molality = moles/ weight of solvent (kg)
And weight (gm)= volume * density
Weight (kg) = volume*density / 1000
And moles = weight/ molecular weight
Molecular weight of NaOH = 40
Putting the values we get:
∴ Molarity = [10/40] * [1000/ (200*1.4)]
Molarity = 0.89 m
Therefore the molarity of solution is 0.89 m.
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