calculate the molarity of 30 grams of Co(NO3)2.6H2O in 4.3 litres of solution
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➡ HERE IS YOUR ANSWER
➡ M = w / GMW × 1 / V (LIT)
➡ w = 30 g
➡ GMW = 291.034 g
➡ V (LIT) = 4.3 lit
➡ M = ?
➡ M = w / GMW × 1 / V (LIT)
➡ M = 30 / 291.034 × 1 / 4.3
➡ M = 30 / 1251.4462
➡ M = 0.023
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♣ HOPE IT HELPS ♣
➡ MARK MY ANSWER BRAINLIEST
---------------------------------------------------------------------------------------♣♣♣
♣ HI FRIEND ♣
---------------------------------------------------------------------------------------♣♣♣
➡ HERE IS YOUR ANSWER
➡ M = w / GMW × 1 / V (LIT)
➡ w = 30 g
➡ GMW = 291.034 g
➡ V (LIT) = 4.3 lit
➡ M = ?
➡ M = w / GMW × 1 / V (LIT)
➡ M = 30 / 291.034 × 1 / 4.3
➡ M = 30 / 1251.4462
➡ M = 0.023
---------------------------------------------------------------------------------------♣♣♣
♣ HOPE IT HELPS ♣
➡ MARK MY ANSWER BRAINLIEST
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