Question

Calculate the molarity of CaCl2 when it is dessolved in 250 ml of the solution and gives 3.011 × 10 to the power 23 chloride ions

Answer 1

Answer:

Explanation:

Since CaCl2 has 2 chloride ions, the number of CaCl2 “molecules” in 200mL is 

= 3.01x10^22 ÷ 2 

= 3.01x10^22 ÷ 2 x 5 per litre 

= 7.525 x 10^22 “molecules” 

1 mole of a substance contains 6.02 x 10^23 “molecules” 

Therefore, number of “molecules” of CaCl2 / litre 

= 7.525 x 10^22 ÷ 6.02 x 10^23 

= 0.125 

CaCl2 solution is 0.125 M

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