Question

Calculate the molarity of H2O2 labelled as 10 volume of H2O2​

Answer 1

Explanation:

The molarity is obtained as moles of solute in 1 L (1000 mL) of solution. In your case, 1 L of solution contains 300 g of H2O2 (PM=34.01 g/mol). Therefore, the molarity is (300 g/34.01 g/mol) = 8.82 M.

Answer 2

Answer:

30% W/V H2O2 means that for each 100 mL of solution there are 30 g of hydrogen peroxide. The molarity is obtained as moles of solute in 1 L (1000 mL) of solution. In your case, 1 L of solution contains 300 g of H2O2 (PM=34.01 g/mol). Therefore, the molarity is (300 g/34.01 g/mol) = 8.82 M.

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