Chemistry, asked by rupeshpatel672, 1 month ago

Calculate the molecular masses of the following and find the percentage of hydrogen in given compound Nitric acid (HNo3) Glucose ( C6 H12 O6) water (H2O )Ammonia (NH3) (H=1, N=14, C=12, O=16)percentage composition of Oxygen=26.24% ,Hydrogen=4.92 % Carbon=68.84%​

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Answered by kirpapatel78
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Explanation:

:(a ... - Toppr

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Calculate the molecular masses of the following :(a) Hydrogen , H2 (b) Oxygen , O2 (c) Chlorine , Cl2 (d) Ammonia , NH3 (e) Carbon dioxide , CO2 (Atomic ...

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(a) Molecular mass of Hydrogen (H2) = 2 × H = 2 × 1 u = 2 u (b) Molecular mass of Oxygen (O2) = 2 × O = 2 × 16 u = 32 u (c) Molecular mass of Chlorine ..

Answered by 12llRoyalQueenll12
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(a) Molecular mass of Hydrogen (H

(a) Molecular mass of Hydrogen (H 2

(a) Molecular mass of Hydrogen (H 2

(a) Molecular mass of Hydrogen (H 2 )=2×H=2×1u=2u

(a) Molecular mass of Hydrogen (H 2 )=2×H=2×1u=2u

(a) Molecular mass of Hydrogen (H 2 )=2×H=2×1u=2u (b) Molecular mass of Oxygen (O

(a) Molecular mass of Hydrogen (H 2 )=2×H=2×1u=2u (b) Molecular mass of Oxygen (O 2

(a) Molecular mass of Hydrogen (H 2 )=2×H=2×1u=2u (b) Molecular mass of Oxygen (O 2

(a) Molecular mass of Hydrogen (H 2 )=2×H=2×1u=2u (b) Molecular mass of Oxygen (O 2 )=2×O=2×16u=32u

(a) Molecular mass of Hydrogen (H 2 )=2×H=2×1u=2u (b) Molecular mass of Oxygen (O 2 )=2×O=2×16u=32u (c) Molecular mass of Chlorine (Cl

(a) Molecular mass of Hydrogen (H 2 )=2×H=2×1u=2u (b) Molecular mass of Oxygen (O 2 )=2×O=2×16u=32u (c) Molecular mass of Chlorine (Cl 2

(a) Molecular mass of Hydrogen (H 2 )=2×H=2×1u=2u (b) Molecular mass of Oxygen (O 2 )=2×O=2×16u=32u (c) Molecular mass of Chlorine (Cl 2

(a) Molecular mass of Hydrogen (H 2 )=2×H=2×1u=2u (b) Molecular mass of Oxygen (O 2 )=2×O=2×16u=32u (c) Molecular mass of Chlorine (Cl 2 )=2×Cl=2×35.5=71u

(a) Molecular mass of Hydrogen (H 2 )=2×H=2×1u=2u (b) Molecular mass of Oxygen (O 2 )=2×O=2×16u=32u (c) Molecular mass of Chlorine (Cl 2 )=2×Cl=2×35.5=71u (d) Molecular mass of Ammonia (NH

(a) Molecular mass of Hydrogen (H 2 )=2×H=2×1u=2u (b) Molecular mass of Oxygen (O 2 )=2×O=2×16u=32u (c) Molecular mass of Chlorine (Cl 2 )=2×Cl=2×35.5=71u (d) Molecular mass of Ammonia (NH 3

(a) Molecular mass of Hydrogen (H 2 )=2×H=2×1u=2u (b) Molecular mass of Oxygen (O 2 )=2×O=2×16u=32u (c) Molecular mass of Chlorine (Cl 2 )=2×Cl=2×35.5=71u (d) Molecular mass of Ammonia (NH 3

(a) Molecular mass of Hydrogen (H 2 )=2×H=2×1u=2u (b) Molecular mass of Oxygen (O 2 )=2×O=2×16u=32u (c) Molecular mass of Chlorine (Cl 2 )=2×Cl=2×35.5=71u (d) Molecular mass of Ammonia (NH 3 )=1×N+3×H=14+3=17u

(a) Molecular mass of Hydrogen (H 2 )=2×H=2×1u=2u (b) Molecular mass of Oxygen (O 2 )=2×O=2×16u=32u (c) Molecular mass of Chlorine (Cl 2 )=2×Cl=2×35.5=71u (d) Molecular mass of Ammonia (NH 3 )=1×N+3×H=14+3=17u (e) Molecular mass of Carbon dioxide (CO

(a) Molecular mass of Hydrogen (H 2 )=2×H=2×1u=2u (b) Molecular mass of Oxygen (O 2 )=2×O=2×16u=32u (c) Molecular mass of Chlorine (Cl 2 )=2×Cl=2×35.5=71u (d) Molecular mass of Ammonia (NH 3 )=1×N+3×H=14+3=17u (e) Molecular mass of Carbon dioxide (CO 2

(a) Molecular mass of Hydrogen (H 2 )=2×H=2×1u=2u (b) Molecular mass of Oxygen (O 2 )=2×O=2×16u=32u (c) Molecular mass of Chlorine (Cl 2 )=2×Cl=2×35.5=71u (d) Molecular mass of Ammonia (NH 3 )=1×N+3×H=14+3=17u (e) Molecular mass of Carbon dioxide (CO 2

(a) Molecular mass of Hydrogen (H 2 )=2×H=2×1u=2u (b) Molecular mass of Oxygen (O 2 )=2×O=2×16u=32u (c) Molecular mass of Chlorine (Cl 2 )=2×Cl=2×35.5=71u (d) Molecular mass of Ammonia (NH 3 )=1×N+3×H=14+3=17u (e) Molecular mass of Carbon dioxide (CO 2 )=1×C+2×O=12+32=44u

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