Question

Calculate the no. of atoms present in 1.4gm of N2 molecule

Answer 1

Explanation:

Since nitrogen is diatomic, the number of atoms would be twice the number of molecules. So, number of atoms in 1.4 gm

nitrogen=(2*6.023*10²²)÷2=6.023*10²²

molecules.

Atomic weight of Nitrogen is 28, and is diatomic.

Answer 2

Answer:

Hope my answer helps you mate :-)

Explanation:

Number of atoms =6.022 × 10²³

Number of atoms =6.022 × 10²³Given weight of N₂ gas = 1.4 g

Number of atoms =6.022 × 10²³Given weight of N₂ gas = 1.4 gMolar mass of N₂ gas = 28 g

Number of atoms =6.022 × 10²³Given weight of N₂ gas = 1.4 gMolar mass of N₂ gas = 28 gSo, mole = given mass/ molar mass

Number of atoms =6.022 × 10²³Given weight of N₂ gas = 1.4 gMolar mass of N₂ gas = 28 gSo, mole = given mass/ molar mass⇒ mole = 1.4/28 = 1/20 mole

Number of atoms =6.022 × 10²³Given weight of N₂ gas = 1.4 gMolar mass of N₂ gas = 28 gSo, mole = given mass/ molar mass⇒ mole = 1.4/28 = 1/20 moleNow, number of molecules = mole × avogadro number

Number of atoms =6.022 × 10²³Given weight of N₂ gas = 1.4 gMolar mass of N₂ gas = 28 gSo, mole = given mass/ molar mass⇒ mole = 1.4/28 = 1/20 moleNow, number of molecules = mole × avogadro number⇒ number of molecules = 1/20 × 6.022 × 10²³

Number of atoms =6.022 × 10²³Given weight of N₂ gas = 1.4 gMolar mass of N₂ gas = 28 gSo, mole = given mass/ molar mass⇒ mole = 1.4/28 = 1/20 moleNow, number of molecules = mole × avogadro number⇒ number of molecules = 1/20 × 6.022 × 10²³⇒ number of molecules = 3.011 × 10²²

Number of atoms =6.022 × 10²³Given weight of N₂ gas = 1.4 gMolar mass of N₂ gas = 28 gSo, mole = given mass/ molar mass⇒ mole = 1.4/28 = 1/20 moleNow, number of molecules = mole × avogadro number⇒ number of molecules = 1/20 × 6.022 × 10²³⇒ number of molecules = 3.011 × 10²²Now, we are asked for number of atoms. In N₂, there are 2 atoms, so to obtain number of atoms we will multiply with 2 in number of molecules.

Number of atoms =6.022 × 10²³Given weight of N₂ gas = 1.4 gMolar mass of N₂ gas = 28 gSo, mole = given mass/ molar mass⇒ mole = 1.4/28 = 1/20 moleNow, number of molecules = mole × avogadro number⇒ number of molecules = 1/20 × 6.022 × 10²³⇒ number of molecules = 3.011 × 10²²Now, we are asked for number of atoms. In N₂, there are 2 atoms, so to obtain number of atoms we will multiply with 2 in number of molecules.⇒ number of atoms = 2 × 3.011 × 10²²

Number of atoms =6.022 × 10²³Given weight of N₂ gas = 1.4 gMolar mass of N₂ gas = 28 gSo, mole = given mass/ molar mass⇒ mole = 1.4/28 = 1/20 moleNow, number of molecules = mole × avogadro number⇒ number of molecules = 1/20 × 6.022 × 10²³⇒ number of molecules = 3.011 × 10²²Now, we are asked for number of atoms. In N₂, there are 2 atoms, so to obtain number of atoms we will multiply with 2 in number of molecules.⇒ number of atoms = 2 × 3.011 × 10²²⇒ number of atoms = 6.022 × 10²²

Number of atoms =6.022 × 10²³Given weight of N₂ gas = 1.4 gMolar mass of N₂ gas = 28 gSo, mole = given mass/ molar mass⇒ mole = 1.4/28 = 1/20 moleNow, number of molecules = mole × avogadro number⇒ number of molecules = 1/20 × 6.022 × 10²³⇒ number of molecules = 3.011 × 10²²Now, we are asked for number of atoms. In N₂, there are 2 atoms, so to obtain number of atoms we will multiply with 2 in number of molecules.⇒ number of atoms = 2 × 3.011 × 10²²⇒ number of atoms = 6.022 × 10²²⇒ number of atoms = 6.022 × 10²³

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