The length, breadth and height of a rectangular block are found to be 15.12 ± 0.02 cm, 7.86 ± 0.01 cm and 4.16 ± 0.02 cm, respectively. Compute the percentage error in the volume of the block.
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A question similar to this. Kindly, put the values by yourself.
The length, breadth and height of a rectangular block of wood were measured to be,
1= 12.1324 0.02 cm, b=8.16 +0.01cm, h = 3.46+0.01 cm. Determine the percentage error in the volume
of the block.
Length = 12.13 +0.02 cm = L + ΔL
Breadth = 8.16 +0.01 cm = B + ΔB
Height = 3.46 + 0.01 cm = H + ΔH
Volume = Length * Bredth * Height = V + ΔV
V = LBH = 12.13 * 8.16 * 3.46 = 342.47
ΔV/V = ΔL/L + ΔB/B + ΔH/H
=> ΔV/342.47 = 0.02/12.13 + 0.01/8.16 + 0.01/3.46
=> ΔV = 0.57 + 0.42 + 0.99
=> ΔV = 1.98
Volume = 342.47 + 1.98
% error = (1.98/342.47) * 100 = 0.58 %
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