Question

Calculate the no of molecules present in 1.8 kg of glucose

Answer 1

Answer:

Explanation:

Glucose = C₆H₁₂O₆

1.8kg = 18000g

$number of mole = \frac{given mass}{molecular mass.}$

                        $= \frac{18000}{180}$

                       $= 100 mole$

$1 mole = 6.022\times10x^{23}$

$100 mole = 6.022\times10^{25} molecule$

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